ln3 Method - NumBits

Description

Return the number of bits needed to represent the current value of the large number.

 

More formally, let X be a variable of type ln.  Then n = X.NumBits( ); such that 2ⁿ < X <= 2^(n-1).

Signature

short NumBits( void ) const

Parameters

( none )

Returns

( short )  The number of bits, as described above.

Example

Print the number of bits in X:

ln X; ... cout << X.NumBits( ) << endl;